Cubs Force A Game 7, Defeat Indians, 9-3 – VIDEO

There will be a seventh game in the 2016 Major League Baseball World Series, after the Chicago Cubs defeated the Chicago Cubs on Tuesday night, 9-3, at Progressive Field in Cleveland, Ohio.

That sets of a decisive, winner-take-all game on Wednesday night, in Cleveland.

The Cubs got on the scoreboard first, scoring three runs, all with two outs, in the top half of the first inning, the first coming on a Kris Bryant solo home run to left-centerfield:

Chicago shortstop Addison Russell was responsible for the next 6 runs, driving home two runs with a double, in the top half of the first inning, on a ball that was misplayed by the Cleveland outfield, and followed that with a grand slam homer in the top half of the third inning, to extend the lead to 7-0.

Russell finished with 6 RBI's, which tied a single-game World Series record:

Cleveland scored their first run in the bottom half of the fourth inning, when Mike Napoli singled home Jason Kipnis, to trim the deficit to 7-1, before Kipnis launched a solo homer in the bottom of the fifth, to make it 7-2:

The Cubs put the game completely away in the top half of the ninth inning, when Anthony Rizzo clubbed a two-run homer, to make it 9-2, before the Indians wrapped-up the scoring in the bottom half of the ninth, courtesy of a Roberto Perez RBI single, to make it 9-3, which is how the game ended.

A complete wrap-up is below:

Game 7 is scheduled for 7 pm (CDT) on Wednesday night: